Consider the equation `(x^2 + x + 1)^2-(m-3)(x^2 + x + 1) +m=(1),` where `m` is a real parame
43 views · Published 13 October 2018 · 2:07 · Indexed 21 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Consider the equation `(x^2 + x + 1)^2-(m-3)(x^2 + x + 1) +m=(1),` where `m` is a real parameter. By putting `x^2+x+1=t(2)` then `t gt= 3/4` for real `x` the equation can be transferred to `f(t) = t^2- (m-3)t + m=0`
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