Let `sum_(r=1)^oo1/((2r-1)^2)=(pi^2)/8,"t h e n"sum_(r=1)^oo1/(r^2)` is equal to
1,385 views · Published 13 October 2018 · 2:49 · Indexed 5 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let `sum_(r=1)^oo1/((2r-1)^2)=(pi^2)/8,"t h e n"sum_(r=1)^oo1/(r^2)` is equal to -~-~~-~~~-~~-~- Please watch: "Tips and Tricks for IIT JEE ADVANCED 2018 | LAST 40 DAYS STRATEGY | Success Mantra" https://www.youtube.com/watch?v=7pqoCZTwDv4 -~-~~-~~~-~~-~-
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