`f(x)=(cos^2x)/(1+cosx+cos^2x)` and `g(x)=ktanx+(1-k)sinx-x`, where `k in R, g'(x)=`
15 views · Published 13 October 2018 · 4:05 · Indexed 21 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `f(x)=(cos^2x)/(1+cosx+cos^2x)` and `g(x)=ktanx+(1-k)sinx-x`, where `k in R, g'(x)=`
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