if `x^2+y^2-4x-6y-3=0`, then minimum possible value of the expression `16 [1/(x-2)^2+1/(y-3)^2]...
879 views · Published 11 October 2018 · 4:40 · Indexed 4 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW if `x^2+y^2-4x-6y-3=0`, then minimum possible value of the expression `16 [1/(x-2)^2+1/(y-3)^2]` is equal to:
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