Tangents to the hyperbola `x^2/a^2-y^2/b^2=1` make angle `theta_1,theta_2` with transverse
1,046 views · Published 13 October 2018 · 2:48 · Indexed 29 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Tangents to the hyperbola `x^2/a^2-y^2/b^2=1` make angle `theta_1,theta_2` with transverse axis of a hyperbola. Show that the point of intersection of these tangents lieson the curve `2xy=k(x^2-a^2)` when `tantheta_1+tan theta_2=k`
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