If `sum_(r=1)^nt_r=sum_(k=1)^nsum_(j=1)^ksum_(i=1)^j2`, then `sum_(r=1)^n1/t_r=`
52 views · Published 13 October 2018 · 4:45 · Indexed 8 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `sum_(r=1)^nt_r=sum_(k=1)^nsum_(j=1)^ksum_(i=1)^j2`, then `sum_(r=1)^n1/t_r=`
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