Prove that the maximum value of the functions `sin^p thetacos^q` is at `theta=tan^-1(sqrt(p/q)
829 views · Published 13 October 2018 · 3:25 · Indexed 23 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Prove that the maximum value of the functions `sin^p thetacos^q` is at `theta=tan^-1(sqrt(p/q)).`
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