The sixth term in the expansion of `( sqrt(2^(log(10-3^x))) + (2^((x-2)log3))^(1/5))^m` is equa...
2,356 views · Published 11 October 2018 · 7:23 · Indexed 4 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The sixth term in the expansion of `( sqrt(2^(log(10-3^x))) + (2^((x-2)log3))^(1/5))^m` is equal to 21, if it is known that the binomial coefficient of the 2nd 3rd and 4th terms in the expansion represent, respectively, the first, third and fifth terms of an A.P. (the symbol log stands for logarithm to the base 10) The value of m is
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