Let A= `[a_(ij)]_(nxxn)` where `a_(ij) = i^2-j^2.` Then A is:
446 views · Published 11 October 2018 · 2:54 · Indexed 20 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let A= `[a_(ij)]_(nxxn)` where `a_(ij) = i^2-j^2.` Then A is:
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