The expression `nC_0+4 * nC_1+4^2 nC_2+.....4^(n^n) C_n`, equals
12 views · Published 13 October 2018 · 1:47 · Indexed 5 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The expression `nC_0+4 * nC_1+4^2 nC_2+.....4^(n^n) C_n`, equals
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