`p(lambda)^4+q(lambda)^3+r(lambda)^2+s(lambda)+t = (((lambda^2 + 3lambda) , lambda -1 , lambda+...
1,310 views · Published 11 October 2018 · 3:01 · Indexed 29 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `p(lambda)^4+q(lambda)^3+r(lambda)^2+s(lambda)+t = (((lambda^2 + 3lambda) , lambda -1 , lambda+3) , (lambda +1 , -2lambda , lambda-4 ) ,(lambda-3 , lambda+4 , 3lambda))` find t=?
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