Given A(2, 1) B(3, -2) find third Point on Line y = x + 3 for area of triangle to be 5 Challenge
3,245 views · Published 18 August 2018 · 6:17 · Indexed 26 September 2026
Channel: Anil Kumar · 2018 · Education
Area of Triangle Playlist: https://www.youtube.com/watch?v=afwfbVADezM&list=PLJ-ma5dJyAqob-oc255AwRAtapJx1mUp0&index=1 Formula Derivation and Examples: https://www.youtube.com/watch?v=afwfbVADezM&list=PLJ-ma5dJyAqob-oc255AwRAtapJx1mUp0 Playlist Coordinate Geometry: https://www.youtube.com/watch?v=CrE7YYhtWl4&list=PLJ-ma5dJyAqpVKB3BKkY26C7L4aYBnXII&index=1 https://www.youtube.com/@MathematicsTutor e-mail: [email protected] Previous Test Analytic Geometry MPM2D: https://www.youtube.com/watch?v=KEeeIaMdjUM&list=PLJ-ma5dJyAqpP4bN-J0MJnpfbbp12539o&index=7 #mpm2d_geometry #mpm2d_areaoftriangle #mpm2d #analyticgeometry #coordinategeometryclass10 #igcse #GCSE #SAT #IBSL #areaoftriangle #precalculus #anilkumarmath #anilkumar #globalmathinstitute #GCSE #SAT The area of triangle is 5 and two of its vertices are A(2,1),B(3,-2).Then find the third vertex in first quadrant which lies on the line y = x + 3.
