Vector Prove Sum of Medians (GP) ̅+(GQ) ̅+(GR) ̅ = 0 where G is the Centroid
3,088 views · Published 6 February 2015 · 4:40 · Indexed 8 October 2026
Channel: Anil Kumar · 2015 · People & Blogs
Vectors Test: https://www.youtube.com/watch?v=Jlhm9hCMN5g&list=PLJ-ma5dJyAqr1h7rcDHhj5q_5OCUeGdfF&index=3 https://www.youtube.com/watch?v=KMPrzZ4NTtc IB MCV4U Test on Introduction of Vectors: https://www.youtube.com/watch?v=LDL-taYc0X0&list=PLJ-ma5dJyAqr5abMalSbaTxeDzT_itkYs&index=1 https://www.youtube.com/@MathematicsTutor Learn From Anil Kumar: [email protected] #vectors_MCV4U #anilkumar #globalmathinstitute #edexcel #vectors #vectors_IBmath #vectors_application #vector_geometry #MCV4U_Vectors #octants #directioncosines The three medians of ∆PQR meet at a common point G. The point G divides each median in a ratio of 2:1. Prove that (GP) ̅+(GQ) ̅+(GR) ̅=0 Let O be midpoint of PR (GP) ̅+(GQ) ̅+(GR) ̅ =(GP) ̅+2(OG) ̅+(GR) ̅ =(GP) ̅+2((OR) ̅+(RG) ̅ )+(GR) ̅ =(GP) ̅+2(OR) ̅+2(RG) ̅+(GR) ̅ =(GP) ̅+(PR) ̅-2(GR) ̅+(GR) ̅ =(GR) ̅-2(GR) ̅+(GR) ̅ =2(GR) ̅-2(GR) ̅=0
