Let r quantities be in an A.P. with common difference 'a'. The A.M. of squares of these quanti
11 views · Published 13 October 2018 · 10:13 · Indexed 2 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let r quantities be in an A.P. with common difference 'a'. The A.M. of squares of these quantitiesa exceed the square of A.M. of these quantities by 'k' and, `(a(r+1))/(3k)=lambda/(a(r-1)),` then `lambda` is
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