`(1/{sec^2 alpha-cos^2 alpha}+1/{cosec^2 alpha-sin^2 alpha})cos^2 alpha*sin^2 alpha=(1-cos^2alp...
4,024 views · Published 12 October 2018 · 5:39 · Indexed 21 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `(1/{sec^2 alpha-cos^2 alpha}+1/{cosec^2 alpha-sin^2 alpha})cos^2 alpha*sin^2 alpha=(1-cos^2alpha*sin^2alpha)/(2+cos^2alpha*sin^2alpha)`
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