Two adjacent sides of a rhombus are given by `2x^2 - 47xy +2y^2 = 0`. If length of the shorter
271 views · Published 13 October 2018 · 4:11 · Indexed 30 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Two adjacent sides of a rhombus are given by `2x^2 - 47xy +2y^2 = 0`. If length of the shorter diagonal passing through their point of intersection is `10sqrt2` Then find the total number of possible positions of the vertex lying on it other than origin.
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