`f(x)={(x^2-x-6)/(x-3);"if"x!=3 5"if"x=3` Show that f(x) is continuous at x=3.
139 views · Published 11 October 2018 · 2:51 · Indexed 6 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `f(x)={(x^2-x-6)/(x-3);"if"x!=3
5"if"x=3`
Show that f(x) is continuous at x=3.
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