Let `(6sqrt(6)+14)^(2n+1)=R`, if R be the fractional part of R, then prove that `Rf=20^(2n+1)`
910 views · Published 11 October 2018 · 6:20 · Indexed 29 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let `(6sqrt(6)+14)^(2n+1)=R`, if R be the fractional part of R, then prove that `Rf=20^(2n+1)`
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