The trigonometric form of `z = (1-icot 8)^3` (where `i = sqrt-1`) is
177 views · Published 13 October 2018 · 3:04 · Indexed 8 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The trigonometric form of `z = (1-icot 8)^3` (where `i = sqrt-1`) is
More from this channel
-
3:35
IIT JEE RELATIONS AND FUNCTIONS Find the period of
`f(x)=sinx+tanx/2+sinx/(2^2)+t a n x/(2^3)++si...
-
4:30
IIT JEE APPLICATION OF DERIVATIVES Find the equation of tangent to the curve
`y=sin^(-1)(2x)/(1+...
-
2:28
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xrarr0)(sinx^0)/x`
-
4:15
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xvecpi/4)(sqrt(2)cosx-1)/(cotx-1)`
-
1:56
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`lim_(x- gt 0)(tan2x-x)/(3x-sinx)`
-
3:15
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xvec2)(x-2)/((log)_a(x-1))`
-
4:29
IIT JEE LIMITS AND DERIVATIVES Evaluate the limit:
`("lim")_(xvecoo)((x+2)/(x+1))^(x+3)`
-
16:12
JEE MAINS 2018 Three persons A, B, CL throw a die in succession till one gets a six
and wins ...