Let `r` be a root of the equation `x^2+2x+6=0`. The value of `(r+2)(r+3)(r+4)(r+5)` is
798 views · Published 11 October 2018 · 2:36 · Indexed 21 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let `r` be a root of the equation `x^2+2x+6=0`. The value of `(r+2)(r+3)(r+4)(r+5)` is
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