Autoplay Next video from Max length

IIT JEE CONIC SECTIONS Prove that the area bounded by the circle `x^2+y^2=a^2` and the ellipse ...

144 views · Published 26 September 2017 · 2:35 · Indexed 21 September 2026

Channel: Doubtnut · 2017 · Education

This is the Solution of question from Cengage Publication Math Book Coordinate Geometry Chapter 6 CONIC SECTIONS written By G. Tewani. You can Find Solution of all math questions from CENGAGE BOOK on our app DOUBTNUT for free. Download Doubtnut from - https://doubtnut.app.link/5ncCEiTYvR

Prove that the area bounded by the circle `x^2+y^2=a^2`
and the
 ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1`
is equal to
 the area of another ellipse having semi-axis `a-b`
and `b ,a gt b`
.

==== SCORE 100% WITH DOUBTNUT ====

Doubtnut ऍप पर आप कक्षा ६ से १२ (IIT JEE तक) के NCERT and IIT JEE Mains & Advanced के मैथ/गणित के सभी सवालों के वीडियो देखिये और मुफ्त में खोजिये किसी भी गणित सवाल का जवाब - १ लाख से भी ज़्यादा सवालों के जवाब हैं Doubtnut ऍप पर.

Doubtnut App has video solutions of ALL the NCERT questions from Class 6 to 12 (including IIT JEE). You can also ask any Math question and get a video solution for FREE from a library of more than 1 Lakh Math Videos.

#jeemains2019 #iitjeemaths #cengage #cengagemaths #cengagesolution #jeemains.

==== FOLLOW US ON====

Website : www.doubtnut.com

Doubtnut PAGE: https://www.facebook.com/doubtnut

DOUBTNUT IIT JEE Group: https://www.facebook.com/groups/251747588948573

IIT JEE CONIC SECTIONS Prove that the area bounded by the circle `x^2+y^2=a^2` and the ellipse ...

More from this channel