`tan theta . tan phi = sqrt((a-b)/(a+b))` , then `(a-b cos 2theta)(a-bcos 2phi)=`
1,091 views · Published 12 October 2018 · 5:46 · Indexed 8 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `tan theta . tan phi = sqrt((a-b)/(a+b))` , then `(a-b cos 2theta)(a-bcos 2phi)=`
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