Let `h(x) = min {x, x^2}`, for every real number of X. Then (A) h is continuous for all x (B) h...
2,032 views · Published 12 October 2018 · 5:00 · Indexed 24 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Let `h(x) = min {x, x^2}`, for every real number of X. Then (A) h is continuous for all x (B) h is differentiable for all x (C) `h^'(x)` = 1, for all x gt 1 (D) h is not differentiable at two values of x
More from this channel
-
4:29
IIT JEE LIMITS AND DERIVATIVES Evaluate the limit:
`("lim")_(xvecoo)((x+2)/(x+1))^(x+3)`
-
3:50
`A D` and `B E` are respectively altitudes of an isosceles triangle `A B C` with `A C=B C` . Pro...
-
4:19
IIT JEE PERMUTATIONS AND COMBINATIONS Find the number of distinct rational numbers `x`
such that ...
-
2:15
IIT JEE PERMUTATIONS AND COMBINATIONS Find the sum of the series `sum_(r=1)^n rxxr !dot`
-
2:47
JEE MAINS 2018 Find the points of local maxima and local minima,
if any, of each of the follo...
-
3:03
Find the number of polynomials of the form `x^3+a x^2+b x+c`
that are divisible by `x^2+1,w h e...
-
3:16
IIT JEE PERMUTATIONS AND COMBINATIONS Find the number of ways in which 6 boys and 6 girls can be ...
-
2:26
IIT JEE COMPLEX NUMBERS AND QUADRATIC EQUATIONS Prove that graphs of `y=x^2+2a n dy=3x-4`
never i...