The probabilities of three events `A,B,C` are such that `P(A)=0.3, P(B)=0.4, P(C)=0.8,P(A nn
2,443 views · Published 13 October 2018 · 3:54 · Indexed 7 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The probabilities of three events `A,B,C` are such that `P(A)=0.3, P(B)=0.4, P(C)=0.8,P(A nn B)=0.09, P(Ann C) = 0.28, P(A nn B nn C) 0.08 and P(Auu B uu C) leq 0.75`.Show that `P(B nn C)` lies in the interval `[0.21, 0.46]`.
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