`f(x)=x^2-4|x| and g(x)={min {f(t):-6letlex},x in [-6,0] and max{f(t):0 lt tlex},x in (0,6],`
121 views · Published 13 October 2018 · 7:01 · Indexed 30 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `f(x)=x^2-4|x| and g(x)={min {f(t):-6letlex},x in [-6,0] and max{f(t):0 lt tlex},x in (0,6],` then `g(x)` has
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