The range of the function `f(theta)=sqrt(8sin^2theta+4cos^2theta-8sinthetacostheta)` is
1,460 views · Published 12 October 2018 · 4:15 · Indexed 2 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The range of the function `f(theta)=sqrt(8sin^2theta+4cos^2theta-8sinthetacostheta)` is
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