The sum `sum_(n=1)^oo tan^(-1)(3/(n^2+n-1))` is equal to

105 views · Published 13 October 2018 · 3:51 · Indexed 26 September 2026

Channel: Doubtnut · 2018 · Education

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To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The sum `sum_(n=1)^oo tan^(-1)(3/(n^2+n-1))` is equal to

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