If `omega !=1` is a cube root of unity, then roots of `(x-2i)^3 +i = 0`
32 views · Published 12 October 2018 · 1:53 · Indexed 30 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `omega !=1` is a cube root of unity, then roots of `(x-2i)^3 +i = 0`
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