In a `triangleABC` `sin^4A+sin^4B+ sin^4C=3/2+2cosAcosBcosC+1/2cos2Acos2Bcos2C`
124 views · Published 11 October 2018 · 6:07 · Indexed 23 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW In a `triangleABC` `sin^4A+sin^4B+ sin^4C=3/2+2cosAcosBcosC+1/2cos2Acos2Bcos2C`
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