Prove that `int_0^x [x]dx=x[x]-1/2[x] ([x]+1)`
13 views · Published 13 October 2018 · 3:59 · Indexed 20 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Prove that `int_0^x [x]dx=x[x]-1/2[x] ([x]+1)`
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