`(tan5A+tan3A)/(tan5-tan3A)=4cos4Acos2A` tan 5A + tan3A - 4cos 4A cos2Atan5A - tan 3A
3,882 views · Published 13 October 2018 · 2:30 · Indexed 28 September 2026
Channel: Doubtnut · 2018 · Education
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