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IIT JEE INTEGRALS Find the equation of tangent to `y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.`

35 views · Published 23 September 2017 · 2:05 · Indexed 20 September 2026

Channel: Doubtnut · 2017 · Education

This is the Solution of question from Cengage Publication Math Book Calculus Chapter 6 INTEGRALS written By G. Tewani. You can Find Solution of all math questions from CENGAGE BOOK on our app DOUBTNUT for free. Download Doubtnut from - https://doubtnut.app.link/3i24JZhkxR

Find the equation of tangent to 
`y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.`

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IIT JEE INTEGRALS Find the equation of tangent to `y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.`

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