If `tanx=tanycos2alpha` prove that : `tan(y-x)=[tan^2alpha.sin2y]/[1+tan^2alpha.cos2y]`
18 views · Published 11 October 2018 · 6:18 · Indexed 30 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `tanx=tanycos2alpha` prove that : `tan(y-x)=[tan^2alpha.sin2y]/[1+tan^2alpha.cos2y]`
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