If `ax^2 - bx + 5 = 0` does not have two distinct real roots. Then find the minimum of `5a+b`
4,347 views · Published 13 October 2018 · 3:51 · Indexed 5 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `ax^2 - bx + 5 = 0` does not have two distinct real roots. Then find the minimum of `5a+b`
More from this channel
-
4:30
IIT JEE APPLICATION OF DERIVATIVES Find the equation of tangent to the curve
`y=sin^(-1)(2x)/(1+...
-
2:28
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xrarr0)(sinx^0)/x`
-
4:15
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xvecpi/4)(sqrt(2)cosx-1)/(cotx-1)`
-
1:56
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`lim_(x- gt 0)(tan2x-x)/(3x-sinx)`
-
3:15
IIT JEE LIMITS AND DERIVATIVES Evaluate:
`("lim")_(xvec2)(x-2)/((log)_a(x-1))`
-
4:29
IIT JEE LIMITS AND DERIVATIVES Evaluate the limit:
`("lim")_(xvecoo)((x+2)/(x+1))^(x+3)`
-
16:12
JEE MAINS 2018 Three persons A, B, CL throw a die in succession till one gets a six
and wins ...
-
3:50
`A D` and `B E` are respectively altitudes of an isosceles triangle `A B C` with `A C=B C` . Pro...