If `alpha` be the real cube root of and `beta`, `gamma` be the complex cube roots of `m`, a rea...
233 views · Published 11 October 2018 · 4:47 · Indexed 3 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `alpha` be the real cube root of and `beta`, `gamma` be the complex cube roots of `m`, a real positive number, then for any `x`, `y`, `z` show that `(xbeta+ygamma+zalpha)/(xgamma+yalpha+zbeta)=omega^2`, where `omega` is a complex cube root of unity.
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