If `x= 2+5i` (where `i^2 =-1) and 2(1/(1!9!)+1/(3!7!))+1/(5!5!)=2^a/(b!)`, then the value of
129 views · Published 13 October 2018 · 7:58 · Indexed 23 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `x= 2+5i` (where `i^2 =-1) and 2(1/(1!9!)+1/(3!7!))+1/(5!5!)=2^a/(b!)`, then the value of `(x^3 - 5x^2 + 33x - 19)` is equal to
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