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Closed Interval Method: Trigonometry Example

896 views · Published 5 February 2014 · 10:28 · Indexed 4 October 2026

Channel: Math Easy Solutions · 2014 · Education

In this video I go over another example on using the closed interval method for determining the absolute maximum and minimum from a continuous function on a closed interval. The example I go over in this video is finding the absolute min and max of the trigonometric function: y = x - 2sin(x) on the interval from 0 to 2pi.

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Related Videos:

Closed Interval Method: Introduction and Example: http://youtu.be/7g_YEsZb04o
Fermat's Theorem: Proof + Biography of Pierre Fermat: http://youtu.be/Sz1gz2lODlo
Critical Numbers: Definition and Example: http://youtu.be/JLdwtzqLxsc
Maximum and Minimum Values: Introduction: http://youtu.be/hkxA4dnnkKs
Maximum and Minimum Values: Examples: http://youtu.be/t-z8LnGb7K0
Extreme Value Theorem: http://youtu.be/UVVJPzce6M8
Types of Intervals - Closed vs Open Intervals: http://youtu.be/wGthQDEixcw
Trigonometry: Sine, Cosine and Tan Functions: http://youtu.be/WKTIlF2oWw8
Derivative of Trigonometry Functions: Derivative of sin(x): http://youtu.be/elEvQ4Wu7Pk
Exact Trigonometry Ratios Part 1: 0, 30, 45, 60, and 90 Degrees: http://youtu.be/ln03a5KvQAY .

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Closed Interval Method: Trigonometry Example

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