`a_k=1/(k(k+1))` for `k=1,2,3,4,...n` then `(sum_(k=1)^n a_k)^2=`
389 views · Published 13 October 2018 · 1:50 · Indexed 7 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `a_k=1/(k(k+1))` for `k=1,2,3,4,...n` then `(sum_(k=1)^n a_k)^2=`
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