If `U_n=|(n,1,5),(n^2, 2N+1,2N+1),(n^3,3N^2,3N+1)|`, then `sum_(n=1)^NU_n` is equal to
395 views · Published 11 October 2018 · 9:33 · Indexed 23 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `U_n=|(n,1,5),(n^2, 2N+1,2N+1),(n^3,3N^2,3N+1)|`, then `sum_(n=1)^NU_n` is equal to
More from this channel
-
4:29
IIT JEE LIMITS AND DERIVATIVES Evaluate the limit:
`("lim")_(xvecoo)((x+2)/(x+1))^(x+3)`
-
3:50
`A D` and `B E` are respectively altitudes of an isosceles triangle `A B C` with `A C=B C` . Pro...
-
4:19
IIT JEE PERMUTATIONS AND COMBINATIONS Find the number of distinct rational numbers `x`
such that ...
-
2:15
IIT JEE PERMUTATIONS AND COMBINATIONS Find the sum of the series `sum_(r=1)^n rxxr !dot`
-
2:47
JEE MAINS 2018 Find the points of local maxima and local minima,
if any, of each of the follo...
-
3:03
Find the number of polynomials of the form `x^3+a x^2+b x+c`
that are divisible by `x^2+1,w h e...
-
3:16
IIT JEE PERMUTATIONS AND COMBINATIONS Find the number of ways in which 6 boys and 6 girls can be ...
-
2:26
IIT JEE COMPLEX NUMBERS AND QUADRATIC EQUATIONS Prove that graphs of `y=x^2+2a n dy=3x-4`
never i...