The polynomial given by `2000 x^6+100 x^5+10 x^3+x-2=0,` has exactly 2 real solutions, one of
17 views · Published 13 October 2018 · 4:27 · Indexed 27 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The polynomial given by `2000 x^6+100 x^5+10 x^3+x-2=0,` has exactly 2 real solutions, one of which is of the form `(a+sqrtb)/c(a=-1).` Then the value of `(a+b)/c` will be
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