What is `[(sin (pi)/6 +i(1-cos (pi/6)))/(sin (pi)/6 +-(1-cos (pi/6)))]^3` where `i=sqrt(-1)` eq...
1,733 views · Published 11 October 2018 · 4:21 · Indexed 23 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW What is `[(sin (pi)/6 +i(1-cos (pi/6)))/(sin (pi)/6 +-(1-cos (pi/6)))]^3` where `i=sqrt(-1)` equal to
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