If equation of the circle is in the form of `x^2+y^2+2gx+2fy+c=0` then prove that its centre
1,314 views · Published 13 October 2018 · 3:52 · Indexed 21 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If equation of the circle is in the form of `x^2+y^2+2gx+2fy+c=0` then prove that its centre and radius will be `(-g, -f)` and `sqrt(g^2+f^2-c)` respectively.
More from this channel
-
4:29
IIT JEE LIMITS AND DERIVATIVES Evaluate the limit:
`("lim")_(xvecoo)((x+2)/(x+1))^(x+3)`
-
4:19
IIT JEE PERMUTATIONS AND COMBINATIONS Find the number of distinct rational numbers `x`
such that ...
-
2:47
JEE MAINS 2018 Find the points of local maxima and local minima,
if any, of each of the follo...
-
3:54
IIT JEE COMPLEX NUMBERS AND QUADRATIC EQUATIONS Find how many roots of the equations `x^4+2x^2-8x...
-
3:54
IIT JEE TRIGONOMETRIC FUNCTIONS One of the general solutions of `sqrt(3) cos theta-3 sin theta=4 ...
-
3:31
IIT JEE TRIGONOMETRIC FUNCTIONS In a triangle, if the angles `A , B ,a n dC`
are in A.P. show tha...
-
2:49
IIT JEE COMPLEX NUMBERS AND QUADRATIC EQUATIONS Find the complex number `z`
satisfying `R e(z^2 ...
-
3:00
IIT JEE TRIGONOMETRIC FUNCTIONS If the area of the circle is `A_1`
and the area of the regular pe...