Prove that the tangent to the parabola `y^2=4ax` at `(a/(m^2),(2a)/m)` is `y=m x+a/m.`

215 views · Published 13 October 2018 · 2:10 · Indexed 4 October 2026

Channel: Doubtnut · 2018 · Education

Watch on YouTube

To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Prove that the tangent to the parabola `y^2=4ax` at `(a/(m^2),(2a)/m)` is `y=m x+a/m.`

More from this channel