If `n_1=`number of ways of outcomes if 2 alike and 4 different dice are thrown, `n_2=`number o
67 views · Published 13 October 2018 · 8:06 · Indexed 2 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `n_1=`number of ways of outcomes if 2 alike and 4 different dice are thrown, `n_2=`number of ways of outcomes if 6 alike dice are thrown then `n_3 =` number of divisors of `n_1` of form `4k + 1, k in N`
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