Consider the ellipse `x^2/tan^2alpha+y^2/sec^2alpha=1,` where `alpha in (0,pi/2)`

225 views · Published 13 October 2018 · 3:56 · Indexed 27 September 2026

Channel: Doubtnut · 2018 · Education

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To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Consider the ellipse `x^2/tan^2alpha+y^2/sec^2alpha=1,` where `alpha in (0,pi/2)`

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