If `(lz_2)/(mz_1)` is purely imaginary number then `|(lambda z_1+muz_2)/(lambdaz_1-muz_2)|` is...
606 views · Published 12 October 2018 · 3:04 · Indexed 3 October 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `(lz_2)/(mz_1)` is purely imaginary number then `|(lambda z_1+muz_2)/(lambdaz_1-muz_2)|` is equal to
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