If `x^3-y^3+3xy^2-3x^2y+1=0` then at `(0,1) (dy)/(dx)=`
1,730 views · Published 13 October 2018 · 1:37 · Indexed 29 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW If `x^3-y^3+3xy^2-3x^2y+1=0` then at `(0,1) (dy)/(dx)=`
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