A+B = 90 , then`( tanAtanB + tanAcotB )/(sinAsecB ) - (sin^2B/cos^2A)`
3,857 views · Published 12 October 2018 · 3:11 · Indexed 26 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW A+B = 90 , then`( tanAtanB + tanAcotB )/(sinAsecB ) - (sin^2B/cos^2A)`
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