IIT JEE SEQUENCES AND SERIES In a sequence of `(4n+1)` terms, the first `(2n+1)` terms are n A....
1,117 views · Published 22 September 2017 · 3:47 · Indexed 24 October 2026
Channel: Doubtnut · 2017 · Education
This is the Solution of question from Cengage Publication Math Book Algebra Chapter 6 SEQUENCES AND SERIES written By G. Tewani. You can Find Solution of all math questions from CENGAGE BOOK on our app DOUBTNUT for free. Download Doubtnut from - https://doubtnut.app.link/YfpFurXBxR In a sequence of `(4n+1)` terms, the first `(2n+1)` terms are n A.P. whose common difference is 2, and the last `(2n+1)` terms are in G.P. whose common ratio is 0.5 if the middle terms of the A.P. and LG.P. are equal ,then the middle terms of the sequence is a.`(n .2 n+1)/(2^(2n)-1)` b. `(n .2 n+1)/(2^n-1)` c. `n .2^n` d. none of these ==== SCORE 100% WITH DOUBTNUT ==== Doubtnut ऍप पर आप कक्षा ६ से १२ (IIT JEE तक) के NCERT and IIT JEE Mains & Advanced के मैथ/गणित के सभी सवालों के वीडियो देखिये और मुफ्त में खोजिये किसी भी गणित सवाल का जवाब - १ लाख से भी ज़्यादा सवालों के जवाब हैं Doubtnut ऍप पर. Doubtnut App has video solutions of ALL the NCERT questions from Class 6 to 12 (including IIT JEE). You can also ask any Math question and get a video solution for FREE from a library of more than 1 Lakh Math Videos. #jeemains2019 #iitjeemaths #cengage #cengagemaths #cengagesolution #jeemains. ==== FOLLOW US ON==== Website : www.doubtnut.com Doubtnut PAGE: https://www.facebook.com/doubtnut DOUBTNUT IIT JEE Group: https://www.facebook.com/groups/251747588948573
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