The equation `(cosp-1)x^2 + cosp.x+ sinp=0` in x has real roots. Then the set of values of p is...
1,283 views · Published 12 October 2018 · 2:10 · Indexed 22 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW The equation `(cosp-1)x^2 + cosp.x+ sinp=0` in x has real roots. Then the set of values of p is (a)[0,2`pi`] (b)[-`pi`,0] (c)`[-pi/2,pi/2]` (d)`[0,pi]`
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